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Title: Lebesgue-Stieltjes Measures
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Series: Measure Theory
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YouTube-Title: Measure Theory 13 | Lebesgue-Stieltjes Measures
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Bright video: https://youtu.be/IsmgLGVpLpQ
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Quiz: Test your knowledge
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Subtitle on GitHub: mt13_sub_eng.srt
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Other languages: German version
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Timestamps (n/a)
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Subtitle in English
1 00:00:00,479 –> 00:00:02,269 Hello and welcome to a
2 00:00:02,279 –> 00:00:03,900 new video in the topic of
3 00:00:03,910 –> 00:00:05,010 measure theory.
4 00:00:05,710 –> 00:00:07,409 First, let me thank all the
5 00:00:07,420 –> 00:00:09,170 nice people that support
6 00:00:09,180 –> 00:00:10,890 this channel on steady.
7 00:00:11,789 –> 00:00:13,649 And today’s topic is Lebesgue-Stieltjes
8 00:00:14,579 –> 00:00:15,329 measures.
9 00:00:16,110 –> 00:00:17,389 It sounds like something
10 00:00:17,399 –> 00:00:19,090 different than a normal measure,
11 00:00:19,399 –> 00:00:21,110 but it’s not, it’s just a
12 00:00:21,120 –> 00:00:22,840 way to construct an
13 00:00:22,850 –> 00:00:23,969 ordinary measure.
14 00:00:24,899 –> 00:00:26,829 And in this way, we can start,
15 00:00:26,840 –> 00:00:28,450 we will now construct a
16 00:00:28,459 –> 00:00:29,020 measure.
17 00:00:29,809 –> 00:00:31,569 The only thing we need here
18 00:00:31,579 –> 00:00:33,069 is a monotonically
19 00:00:33,080 –> 00:00:34,590 increasing function
20 00:00:34,599 –> 00:00:36,549 defined on the real number
21 00:00:36,560 –> 00:00:37,020 line.
22 00:00:37,360 –> 00:00:38,979 And when I say monotonically
23 00:00:38,990 –> 00:00:40,790 increasing, I mean
24 00:00:40,799 –> 00:00:41,990 non-decreasing.
25 00:00:42,880 –> 00:00:44,580 In other words, a constant
26 00:00:44,590 –> 00:00:46,150 function is also
27 00:00:46,159 –> 00:00:47,889 monotonically increasing.
28 00:00:48,819 –> 00:00:50,159 The best way to see that
29 00:00:50,169 –> 00:00:51,990 is of course to draw a short
30 00:00:52,009 –> 00:00:53,240 graph of such a function.
31 00:00:54,250 –> 00:00:55,500 So maybe the function is
32 00:00:55,509 –> 00:00:57,200 first increasing here
33 00:00:58,009 –> 00:00:59,880 then at it is constant
34 00:01:01,849 –> 00:01:03,259 and maybe, then we have a
35 00:01:03,270 –> 00:01:05,029 jump point at this point.
36 00:01:05,650 –> 00:01:07,419 So no value here, the value
37 00:01:07,430 –> 00:01:09,150 is here then still the
38 00:01:09,160 –> 00:01:09,989 constant
39 00:01:11,059 –> 00:01:12,550 and maybe after this, it’s
40 00:01:12,559 –> 00:01:13,910 still increasing and then
41 00:01:13,919 –> 00:01:15,839 comes the next jump point.
42 00:01:17,360 –> 00:01:19,300 So here’s the point and then
43 00:01:19,309 –> 00:01:20,910 it goes to an
44 00:01:20,919 –> 00:01:22,290 increasing function till
45 00:01:22,300 –> 00:01:24,029 here and then maybe it’s
46 00:01:24,040 –> 00:01:25,309 constant after that.
47 00:01:26,750 –> 00:01:27,209 OK.
48 00:01:27,220 –> 00:01:29,129 So this is a typical example
49 00:01:29,139 –> 00:01:30,290 of a graph of a
50 00:01:30,300 –> 00:01:31,930 monotonically increasing
51 00:01:31,940 –> 00:01:32,459 function.
52 00:01:33,459 –> 00:01:35,379 In particular, it’s allowed
53 00:01:35,389 –> 00:01:36,660 that the function is
54 00:01:36,669 –> 00:01:38,279 constant at some
55 00:01:38,290 –> 00:01:38,919 parts.
56 00:01:39,610 –> 00:01:41,279 And there could be also points
57 00:01:41,290 –> 00:01:42,470 where the function is non
58 00:01:42,569 –> 00:01:43,459 continuous.
59 00:01:43,470 –> 00:01:45,099 So where we have jumps,
60 00:01:45,529 –> 00:01:46,910 but of course, the jumps
61 00:01:46,919 –> 00:01:48,540 has to go upwards.
62 00:01:49,769 –> 00:01:51,430 Now, with the help of such
63 00:01:51,440 –> 00:01:53,069 a function, we want to
64 00:01:53,080 –> 00:01:54,699 measure the length of
65 00:01:54,709 –> 00:01:55,510 intervals.
66 00:01:56,099 –> 00:01:57,629 First, I want to calculate
67 00:01:57,639 –> 00:01:59,470 intervals of the form A
68 00:01:59,480 –> 00:02:01,389 B where A is
69 00:02:01,400 –> 00:02:02,989 included but B is
70 00:02:03,000 –> 00:02:03,870 excluded
71 00:02:04,900 –> 00:02:06,510 for better visualization,
72 00:02:06,519 –> 00:02:08,070 I can put that here in the
73 00:02:08,080 –> 00:02:08,690 picture.
74 00:02:08,699 –> 00:02:10,589 So here’s A and
75 00:02:10,600 –> 00:02:11,809 there’s our B,
76 00:02:13,630 –> 00:02:15,559 obviously, the normal notion
77 00:02:15,570 –> 00:02:17,130 of the length would be just
78 00:02:17,139 –> 00:02:18,850 B minus
79 00:02:18,860 –> 00:02:19,309 A.
80 00:02:20,259 –> 00:02:22,119 But here I want that F
81 00:02:22,130 –> 00:02:24,039 as a function scales
82 00:02:24,050 –> 00:02:25,720 the length of this interval,
83 00:02:26,139 –> 00:02:27,639 this means that the length
84 00:02:27,649 –> 00:02:29,619 should be longer where the
85 00:02:29,630 –> 00:02:30,929 increase of the function
86 00:02:30,940 –> 00:02:32,179 is stronger.
87 00:02:33,250 –> 00:02:34,669 Therefore, we have to look
88 00:02:34,679 –> 00:02:36,449 what the function does with
89 00:02:36,460 –> 00:02:37,190 the interval.
90 00:02:37,300 –> 00:02:39,110 So we look at the
91 00:02:39,119 –> 00:02:40,729 image of the
92 00:02:40,740 –> 00:02:42,160 interval under the
93 00:02:42,169 –> 00:02:43,229 function F
94 00:02:44,220 –> 00:02:44,940 in the picture.
95 00:02:44,949 –> 00:02:46,419 This would roughly look like
96 00:02:46,429 –> 00:02:46,669 this.
97 00:02:46,679 –> 00:02:48,020 So we have a point
98 00:02:48,229 –> 00:02:50,100 FB here
99 00:02:50,839 –> 00:02:52,320 and F of A
100 00:02:52,330 –> 00:02:53,029 here
101 00:02:55,110 –> 00:02:56,839 scaling the length of this
102 00:02:56,850 –> 00:02:58,009 interval of the function
103 00:02:58,020 –> 00:02:58,419 F.
104 00:02:58,429 –> 00:03:00,410 Now just means we look at
105 00:03:00,419 –> 00:03:01,830 the Y axis here,
106 00:03:02,250 –> 00:03:04,000 which means the length of
107 00:03:04,009 –> 00:03:05,490 this interval which is
108 00:03:05,500 –> 00:03:07,220 just F of
109 00:03:07,229 –> 00:03:08,850 B minus
110 00:03:08,919 –> 00:03:10,110 F of A.
111 00:03:12,059 –> 00:03:12,630 OK.
112 00:03:12,839 –> 00:03:14,789 Now, I hope you immediately
113 00:03:14,800 –> 00:03:16,789 recognized a mistake here.
114 00:03:17,600 –> 00:03:19,589 You see B is not
115 00:03:19,600 –> 00:03:21,259 a point in our interval.
116 00:03:22,050 –> 00:03:23,479 Therefore, it would be wrong
117 00:03:23,490 –> 00:03:24,919 to use this point.
118 00:03:24,929 –> 00:03:26,729 So the image of B we
119 00:03:26,740 –> 00:03:28,559 should rather use this point
120 00:03:28,570 –> 00:03:29,179 here.
121 00:03:29,460 –> 00:03:31,389 This one is the correct point
122 00:03:31,399 –> 00:03:32,710 that describes the right
123 00:03:32,720 –> 00:03:34,300 hand bound of the
124 00:03:34,309 –> 00:03:35,539 image of A B.
125 00:03:36,479 –> 00:03:38,039 Therefore, on the Y axis,
126 00:03:38,050 –> 00:03:39,600 we also have this point
127 00:03:39,610 –> 00:03:40,089 here.
128 00:03:40,100 –> 00:03:41,179 The important one
129 00:03:41,979 –> 00:03:43,160 and I would call it
130 00:03:43,169 –> 00:03:44,960 FB minus in a
131 00:03:44,970 –> 00:03:46,070 short notation.
132 00:03:47,000 –> 00:03:48,589 Therefore, I would also include
133 00:03:48,600 –> 00:03:50,020 the point here on the right
134 00:03:50,080 –> 00:03:51,699 for calculating the length
135 00:03:51,710 –> 00:03:52,580 of the interval.
136 00:03:53,770 –> 00:03:55,550 Well, now you should see
137 00:03:55,559 –> 00:03:57,039 we have the same problem
138 00:03:57,050 –> 00:03:57,509 here.
139 00:03:57,520 –> 00:03:58,729 We have the same problem
140 00:03:58,740 –> 00:04:00,149 on the left hand side with
141 00:04:00,160 –> 00:04:01,820 the point A, you
142 00:04:01,830 –> 00:04:03,720 see A is included in
143 00:04:03,729 –> 00:04:04,610 our interval.
144 00:04:04,619 –> 00:04:05,830 And therefore, we should
145 00:04:05,839 –> 00:04:07,309 include this full
146 00:04:07,320 –> 00:04:08,979 jump in our calculation of
147 00:04:08,990 –> 00:04:10,649 the length of this interval.
148 00:04:11,199 –> 00:04:12,360 On the right hand side, we
149 00:04:12,369 –> 00:04:13,910 ignored the full jump because
150 00:04:13,919 –> 00:04:15,300 B was not in the interval,
151 00:04:15,309 –> 00:04:17,048 but now A is in the
152 00:04:17,059 –> 00:04:17,790 interval.
153 00:04:17,798 –> 00:04:19,750 And therefore we should add
154 00:04:19,760 –> 00:04:21,670 the jump to our calculation.
155 00:04:22,320 –> 00:04:23,619 You see this immediately,
156 00:04:23,630 –> 00:04:25,619 if we change this point
157 00:04:25,630 –> 00:04:27,420 maybe to the middle here,
158 00:04:28,239 –> 00:04:29,359 then we would change the
159 00:04:29,369 –> 00:04:30,450 whole calculation of the
160 00:04:30,459 –> 00:04:32,000 length, but we wouldn’t
161 00:04:32,010 –> 00:04:33,730 change the total jump.
162 00:04:34,670 –> 00:04:36,309 Hence, the only meaningful
163 00:04:36,320 –> 00:04:38,049 way to choose a point here
164 00:04:38,059 –> 00:04:39,619 would be to choose the point
165 00:04:39,630 –> 00:04:41,369 the value at the bottom here.
166 00:04:43,140 –> 00:04:45,100 And as before, I also would
167 00:04:45,109 –> 00:04:46,559 call this in short
168 00:04:46,570 –> 00:04:47,859 by fa
169 00:04:47,869 –> 00:04:49,739 minus and then we
170 00:04:49,750 –> 00:04:51,600 include the minus sign here
171 00:04:51,609 –> 00:04:52,399 as well.
172 00:04:53,109 –> 00:04:54,880 Now this thing is now our
173 00:04:54,890 –> 00:04:56,600 new notion of the length
174 00:04:56,609 –> 00:04:57,559 of an interval.
175 00:04:58,220 –> 00:04:59,380 And of course, I should give
176 00:04:59,390 –> 00:05:00,850 it a name and we call it
177 00:05:01,000 –> 00:05:02,790 mu with index
178 00:05:02,799 –> 00:05:04,109 F of this
179 00:05:04,119 –> 00:05:04,799 interval.
180 00:05:05,790 –> 00:05:07,250 And to be more precise, I
181 00:05:07,260 –> 00:05:08,929 also add the definition
182 00:05:08,940 –> 00:05:10,459 of our FB
183 00:05:10,470 –> 00:05:12,109 minus or FA
184 00:05:12,119 –> 00:05:12,859 minus.
185 00:05:14,269 –> 00:05:16,010 As you can see, this is nothing
186 00:05:16,019 –> 00:05:17,970 else than a left limit.
187 00:05:17,980 –> 00:05:19,429 So we get closer and
188 00:05:19,440 –> 00:05:20,890 closer coming from the
189 00:05:20,899 –> 00:05:21,489 left.
190 00:05:22,299 –> 00:05:23,910 Therefore, we can write this
191 00:05:23,970 –> 00:05:25,609 as an epsilon that goes to
192 00:05:25,619 –> 00:05:27,500 zero plus, which means
193 00:05:27,510 –> 00:05:29,119 it’s an epsilon greater than
194 00:05:29,130 –> 00:05:31,000 zero that goes to zero.
195 00:05:31,299 –> 00:05:33,079 And then we subtract it
196 00:05:33,089 –> 00:05:34,140 from A
197 00:05:36,769 –> 00:05:38,510 and then you see we get back
198 00:05:38,519 –> 00:05:40,309 the points we have seen in
199 00:05:40,320 –> 00:05:41,350 our drawing here.
200 00:05:42,450 –> 00:05:43,799 And at this point, you are
201 00:05:43,809 –> 00:05:45,390 allowed to ask what
202 00:05:45,399 –> 00:05:46,790 happens if I come from the
203 00:05:46,799 –> 00:05:48,619 right hand side instead of
204 00:05:48,630 –> 00:05:49,670 the left hand side.
205 00:05:50,470 –> 00:05:51,739 And then what you get is
206 00:05:51,750 –> 00:05:53,549 an alternative way to
207 00:05:53,559 –> 00:05:54,369 write this down.
208 00:05:54,380 –> 00:05:55,970 So we have FB
209 00:05:55,980 –> 00:05:56,970 plus
210 00:05:57,559 –> 00:05:58,950 minus FA
211 00:05:58,959 –> 00:06:00,850 plus where the plus
212 00:06:00,859 –> 00:06:02,579 now means the right hand
213 00:06:02,589 –> 00:06:03,250 limit.
214 00:06:05,500 –> 00:06:07,399 Now, if you go back to our
215 00:06:07,410 –> 00:06:09,359 graph, then you see,
216 00:06:09,369 –> 00:06:10,720 now we describe
217 00:06:10,730 –> 00:06:12,459 another interval, not
218 00:06:12,470 –> 00:06:14,239 this one because
219 00:06:14,250 –> 00:06:15,920 now we ignore this jump,
220 00:06:15,929 –> 00:06:17,730 but we add this jump on the
221 00:06:17,739 –> 00:06:19,480 right, this means that
222 00:06:19,489 –> 00:06:21,029 we exactly change the
223 00:06:21,040 –> 00:06:22,010 boundaries here.
224 00:06:22,019 –> 00:06:23,959 Now we measure an interval
225 00:06:23,970 –> 00:06:25,559 where A is not
226 00:06:25,570 –> 00:06:26,420 included.
227 00:06:26,730 –> 00:06:28,019 But B is
228 00:06:29,769 –> 00:06:31,630 hence, if you want to work
229 00:06:31,640 –> 00:06:33,549 with these intervals, then
230 00:06:33,559 –> 00:06:34,880 you have to consider the
231 00:06:34,890 –> 00:06:35,950 right hand limit.
232 00:06:36,799 –> 00:06:38,269 I personally want to work
233 00:06:38,279 –> 00:06:39,339 with these intervals.
234 00:06:39,350 –> 00:06:41,130 And therefore, we don’t need
235 00:06:41,140 –> 00:06:42,309 the alternative here.
236 00:06:43,959 –> 00:06:45,739 Nevertheless, it’s very important
237 00:06:45,750 –> 00:06:47,450 to note that if you look
238 00:06:47,459 –> 00:06:48,799 at the points where the function
239 00:06:48,809 –> 00:06:50,619 F is not continuous,
240 00:06:50,989 –> 00:06:52,510 then it does not matter at
241 00:06:52,519 –> 00:06:54,359 all where the value
242 00:06:54,369 –> 00:06:55,850 of the function at this point
243 00:06:55,859 –> 00:06:57,420 is it only
244 00:06:57,429 –> 00:06:58,890 matters what the limit from
245 00:06:58,899 –> 00:07:00,290 the left hand side is.
246 00:07:00,299 –> 00:07:01,450 And what the limit from the
247 00:07:01,459 –> 00:07:02,579 right hand side is
248 00:07:03,350 –> 00:07:04,970 because these two points
249 00:07:04,980 –> 00:07:06,730 describe how large the
250 00:07:06,739 –> 00:07:07,529 jump is.
251 00:07:08,540 –> 00:07:09,290 OK.
252 00:07:09,299 –> 00:07:10,679 I said before, I want to
253 00:07:10,690 –> 00:07:12,320 work with these intervals
254 00:07:12,329 –> 00:07:14,160 here because we know
255 00:07:14,170 –> 00:07:16,119 from another video that
256 00:07:16,130 –> 00:07:17,950 they form a so called semiring.
257 00:07:18,029 –> 00:07:19,809 This is what I
258 00:07:19,820 –> 00:07:21,630 explained to you in the video
259 00:07:21,640 –> 00:07:22,279 about Carathéodory’s
260 00:07:23,130 –> 00:07:24,519 extension theory.
261 00:07:25,250 –> 00:07:27,109 And now we can apply this
262 00:07:27,119 –> 00:07:28,899 theorem to conclude
263 00:07:28,910 –> 00:07:30,709 that we can extend this
264 00:07:30,720 –> 00:07:32,119 definition to a
265 00:07:32,130 –> 00:07:33,869 measure defined on the
266 00:07:33,880 –> 00:07:35,829 full Borel sigma algebra
267 00:07:35,839 –> 00:07:36,510 of R.
268 00:07:37,549 –> 00:07:38,959 This means there is
269 00:07:38,970 –> 00:07:40,839 exactly one measure
270 00:07:40,850 –> 00:07:42,209 defined on
271 00:07:42,220 –> 00:07:43,380 B(R)
272 00:07:44,570 –> 00:07:46,470 to 0 infinity
273 00:07:48,549 –> 00:07:49,929 with the property
274 00:07:50,410 –> 00:07:51,609 that we have here.
275 00:07:52,850 –> 00:07:54,190 So maybe let’s call this
276 00:07:54,200 –> 00:07:56,119 property here star and then
277 00:07:56,130 –> 00:07:58,029 I can write star here.
278 00:07:59,100 –> 00:08:00,940 Now it’s useful to call this
279 00:08:00,950 –> 00:08:02,239 uniquely given measure
280 00:08:02,250 –> 00:08:03,880 again by
281 00:08:03,890 –> 00:08:04,869 mu F.
282 00:08:05,779 –> 00:08:07,670 And if we construct a measure
283 00:08:07,679 –> 00:08:09,579 in this way, we call it a
284 00:08:09,589 –> 00:08:11,440 Lebesgue Stieltjes measure.
285 00:08:12,170 –> 00:08:13,600 And to be more concrete,
286 00:08:13,730 –> 00:08:15,570 you call it the Lebesgue
287 00:08:15,579 –> 00:08:17,399 Stieltjes measure for the
288 00:08:17,410 –> 00:08:18,549 function F
289 00:08:20,660 –> 00:08:22,279 here, you recognize how
290 00:08:22,290 –> 00:08:23,070 strong Carathéodory’s
291 00:08:23,809 –> 00:08:25,299 extension theorem really
292 00:08:25,309 –> 00:08:25,779 is.
293 00:08:26,260 –> 00:08:28,000 You only have to find the
294 00:08:28,010 –> 00:08:29,059 measure for the
295 00:08:29,070 –> 00:08:30,869 intervals and then you get
296 00:08:30,880 –> 00:08:32,719 exactly one measure
297 00:08:32,729 –> 00:08:34,440 for all Borel sets out,
298 00:08:35,460 –> 00:08:36,109 OK.
299 00:08:36,119 –> 00:08:37,558 Now, you know how this
300 00:08:37,570 –> 00:08:38,808 construction works.
301 00:08:39,030 –> 00:08:40,359 And I would suggest that
302 00:08:40,369 –> 00:08:42,320 we now look at examples.
303 00:08:43,179 –> 00:08:44,879 An example means of course,
304 00:08:44,888 –> 00:08:46,679 we choose a monotonically
305 00:08:46,689 –> 00:08:48,528 increasing function capital
306 00:08:48,568 –> 00:08:50,239 F and then we look
307 00:08:50,249 –> 00:08:51,958 what is the associated Lebesgue Stieltjes
308 00:08:52,388 –> 00:08:53,078 measure.
309 00:08:54,109 –> 00:08:54,409 OK.
310 00:08:54,419 –> 00:08:55,690 Maybe the easiest
311 00:08:55,700 –> 00:08:57,590 example is the Lebesgue
312 00:08:57,599 –> 00:08:58,599 measure itself.
313 00:08:58,799 –> 00:09:00,169 For this, we choose
314 00:09:00,179 –> 00:09:01,369 simply the
315 00:09:01,380 –> 00:09:02,190 identity.
316 00:09:02,200 –> 00:09:03,760 So the function FX
317 00:09:03,770 –> 00:09:05,690 equals to X, then
318 00:09:05,700 –> 00:09:07,049 we don’t change the
319 00:09:07,059 –> 00:09:08,840 normal measuring of
320 00:09:08,849 –> 00:09:10,260 lengths of intervals.
321 00:09:10,909 –> 00:09:12,049 So we get out
322 00:09:12,200 –> 00:09:14,109 B minus A
323 00:09:14,340 –> 00:09:15,210 as before.
324 00:09:16,260 –> 00:09:17,919 Hence, we get out our
325 00:09:17,929 –> 00:09:19,719 ordinary Lebesgue measure.
326 00:09:21,010 –> 00:09:22,440 Another example of a
327 00:09:22,450 –> 00:09:23,520 very easy
328 00:09:23,530 –> 00:09:25,229 monotonically increasing
329 00:09:25,239 –> 00:09:27,080 function would be a constant
330 00:09:27,090 –> 00:09:27,640 function.
331 00:09:28,830 –> 00:09:30,809 So let’s choose FX is
332 00:09:30,820 –> 00:09:31,969 equal to one
333 00:09:31,979 –> 00:09:32,849 everywhere.
334 00:09:33,429 –> 00:09:34,969 Obviously, in this case,
335 00:09:34,979 –> 00:09:36,590 measuring the length of
336 00:09:36,599 –> 00:09:38,289 intervals is very boring
337 00:09:39,299 –> 00:09:40,969 because we subtract right
338 00:09:40,979 –> 00:09:41,780 from left.
339 00:09:41,789 –> 00:09:43,500 So we have here everywhere
340 00:09:43,510 –> 00:09:44,400 zero.
341 00:09:45,039 –> 00:09:46,320 Hence this is not so
342 00:09:46,330 –> 00:09:48,159 surprising we get out
343 00:09:48,169 –> 00:09:49,440 our zero measure.
344 00:09:50,299 –> 00:09:50,640 OK.
345 00:09:50,650 –> 00:09:52,580 Maybe more interesting would
346 00:09:52,590 –> 00:09:54,039 be the case where we have
347 00:09:54,049 –> 00:09:55,719 two values for the function.
348 00:09:56,119 –> 00:09:57,919 So constant function, with
349 00:09:57,929 –> 00:09:59,919 the exception of one jump,
350 00:10:00,530 –> 00:10:02,150 for example, we could choose
351 00:10:02,159 –> 00:10:04,059 zero if X is
352 00:10:04,070 –> 00:10:06,010 less than zero and
353 00:10:06,020 –> 00:10:07,780 one if X is
354 00:10:07,789 –> 00:10:09,640 greater or equal than zero.
355 00:10:10,200 –> 00:10:11,869 And please remember it does
356 00:10:11,880 –> 00:10:13,659 not matter where the equality
357 00:10:13,669 –> 00:10:14,630 sign is here.
358 00:10:14,880 –> 00:10:16,159 The measure just doesn’t
359 00:10:16,169 –> 00:10:17,359 care about this.
360 00:10:17,369 –> 00:10:19,020 The measure can’t see this
361 00:10:19,030 –> 00:10:19,950 point there.
362 00:10:20,940 –> 00:10:22,530 Now, obviously, we have the
363 00:10:22,539 –> 00:10:24,359 same result as before.
364 00:10:24,369 –> 00:10:26,169 For all intervals that
365 00:10:26,179 –> 00:10:27,609 lie completely to the left
366 00:10:27,619 –> 00:10:28,280 of zero.
367 00:10:28,289 –> 00:10:29,590 Or completely to the right
368 00:10:29,599 –> 00:10:30,320 of zero.
369 00:10:30,340 –> 00:10:31,500 And we get out again, the
370 00:10:31,510 –> 00:10:32,590 measure zero.
371 00:10:33,739 –> 00:10:35,169 Hence, the interesting
372 00:10:35,179 –> 00:10:36,809 cases would be where
373 00:10:36,820 –> 00:10:38,359 zero is inside the
374 00:10:38,369 –> 00:10:39,080 interval.
375 00:10:39,770 –> 00:10:41,460 For example, let’s look at
376 00:10:41,469 –> 00:10:42,780 the interval minus
377 00:10:42,789 –> 00:10:44,200 epsilon till
378 00:10:44,210 –> 00:10:45,039 epsilon.
379 00:10:45,239 –> 00:10:46,330 Of course, where epsilon
380 00:10:46,340 –> 00:10:48,130 is a positive number.
381 00:10:49,179 –> 00:10:50,989 Now, what do we get on the
382 00:10:51,000 –> 00:10:51,979 right hand side, we have
383 00:10:51,989 –> 00:10:53,750 one on left, we have zero.
384 00:10:53,760 –> 00:10:55,219 So we have one minus
385 00:10:55,229 –> 00:10:55,760 zero.
386 00:10:55,849 –> 00:10:57,359 So we get out one.
387 00:10:58,020 –> 00:10:59,960 And please note this holds
388 00:10:59,969 –> 00:11:01,299 for all epsilon,
389 00:11:02,000 –> 00:11:03,380 we already know a measure
390 00:11:03,390 –> 00:11:05,099 that does this and this
391 00:11:05,109 –> 00:11:06,789 is the Dirac measure at
392 00:11:06,799 –> 00:11:07,369 zero.
393 00:11:08,140 –> 00:11:10,049 Now, by the uniqueness result,
394 00:11:10,059 –> 00:11:11,380 we know that the
395 00:11:11,390 –> 00:11:13,250 extension has to be this
396 00:11:13,559 –> 00:11:14,020 Dirac measure.
397 00:11:14,799 –> 00:11:16,429 So you see we can use this
398 00:11:16,440 –> 00:11:18,229 strong result very often.
399 00:11:19,299 –> 00:11:20,750 Now for the end of the video,
400 00:11:20,760 –> 00:11:22,719 let’s look at a very general
401 00:11:22,729 –> 00:11:23,479 example.
402 00:11:24,080 –> 00:11:25,130 Therefore, let’s choose a
403 00:11:25,140 –> 00:11:26,770 general monotonically
404 00:11:26,780 –> 00:11:28,479 increasing function F
405 00:11:28,900 –> 00:11:30,200 but in addition, it should
406 00:11:30,210 –> 00:11:31,809 also be continuously
407 00:11:31,820 –> 00:11:33,760 differentiable both
408 00:11:33,770 –> 00:11:34,559 things together.
409 00:11:34,570 –> 00:11:35,840 Now means that the
410 00:11:35,849 –> 00:11:37,200 derivative is
411 00:11:37,210 –> 00:11:38,650 continuous and
412 00:11:38,659 –> 00:11:40,650 also has values in the
413 00:11:40,659 –> 00:11:41,909 non-negative
414 00:11:41,919 –> 00:11:42,679 numbers.
415 00:11:44,549 –> 00:11:46,080 On the other hand, F
416 00:11:46,090 –> 00:11:47,450 itself is of course
417 00:11:47,460 –> 00:11:48,369 continuous.
418 00:11:48,380 –> 00:11:50,250 Therefore, there are no jumps.
419 00:11:50,989 –> 00:11:52,210 This means that we don’t
420 00:11:52,219 –> 00:11:53,530 have the problem with the
421 00:11:53,539 –> 00:11:54,500 left hand limit.
422 00:11:54,510 –> 00:11:55,479 And the right hand limit
423 00:11:55,489 –> 00:11:57,210 from before, for this
424 00:11:57,219 –> 00:11:58,450 continuous function, we can
425 00:11:58,460 –> 00:12:00,450 just use the values of the
426 00:12:00,460 –> 00:12:01,049 function.
427 00:12:02,239 –> 00:12:03,640 This means the length of
428 00:12:03,650 –> 00:12:05,219 the interval is nothing
429 00:12:05,229 –> 00:12:06,190 more than
430 00:12:06,200 –> 00:12:08,030 FB minus
431 00:12:08,039 –> 00:12:08,979 FA.
432 00:12:10,380 –> 00:12:12,280 Now, if you learn calculus,
433 00:12:12,289 –> 00:12:13,979 you should immediately recognize
434 00:12:13,989 –> 00:12:14,989 this one here,
435 00:12:15,500 –> 00:12:16,960 namely, here you can
436 00:12:16,969 –> 00:12:18,700 apply the fundamental
437 00:12:18,710 –> 00:12:20,309 theorem of calculus
438 00:12:20,969 –> 00:12:22,840 which tells you this is
439 00:12:22,849 –> 00:12:24,440 the integral of the
440 00:12:24,450 –> 00:12:26,340 derivative of
441 00:12:26,510 –> 00:12:28,299 F dX where
442 00:12:28,309 –> 00:12:30,260 dx just denotes the normal
443 00:12:30,340 –> 00:12:31,200 Lebesgue measure here.
444 00:12:32,520 –> 00:12:32,880 OK.
445 00:12:32,890 –> 00:12:34,380 And this is all we need
446 00:12:34,390 –> 00:12:35,979 because you would believe
447 00:12:35,989 –> 00:12:37,929 me that we can define a
448 00:12:37,940 –> 00:12:38,979 new measure.
449 00:12:39,400 –> 00:12:40,880 So for each Borel set
450 00:12:40,890 –> 00:12:42,739 A, we define the
451 00:12:42,750 –> 00:12:44,479 measure as this
452 00:12:44,489 –> 00:12:45,400 integral.
453 00:12:45,669 –> 00:12:45,690 Yeah.
454 00:12:45,729 –> 00:12:47,520 So we send the Borel
455 00:12:47,549 –> 00:12:49,140 set to this number
456 00:12:49,150 –> 00:12:49,580 here.
457 00:12:50,030 –> 00:12:51,900 This defines us a measure
458 00:12:51,909 –> 00:12:53,619 on the Borel Sigma algebra
459 00:12:53,630 –> 00:12:54,200 of R.
460 00:12:54,739 –> 00:12:56,539 And now we apply the uniqueness
461 00:12:56,549 –> 00:12:58,419 result of Carathéodory’s
462 00:12:58,429 –> 00:12:59,859 extension theorem.
463 00:13:00,320 –> 00:13:01,780 And then we get out that
464 00:13:01,789 –> 00:13:03,700 our measure mu F
465 00:13:03,710 –> 00:13:05,520 looks exactly like this
466 00:13:05,530 –> 00:13:05,859 one.
467 00:13:07,010 –> 00:13:08,419 We know it looks like this
468 00:13:08,429 –> 00:13:10,229 for all intervals
469 00:13:10,239 –> 00:13:11,659 and therefore it should also
470 00:13:11,669 –> 00:13:13,479 look like this for each Borel
471 00:13:13,669 –> 00:13:14,109 set.
472 00:13:14,969 –> 00:13:15,419 OK.
473 00:13:15,429 –> 00:13:16,880 Here you see a very general
474 00:13:16,890 –> 00:13:18,179 result for such
475 00:13:18,950 –> 00:13:19,719 Lebesgue Stieltjes measures.
476 00:13:20,289 –> 00:13:21,859 And this part here in the
477 00:13:21,869 –> 00:13:23,460 integral is then often
478 00:13:23,469 –> 00:13:24,869 called a density
479 00:13:24,880 –> 00:13:25,559 function.
480 00:13:26,570 –> 00:13:28,349 However, that’s a thing we
481 00:13:28,359 –> 00:13:29,830 could discuss in another
482 00:13:29,840 –> 00:13:31,070 video later
483 00:13:31,940 –> 00:13:32,280 here.
484 00:13:32,289 –> 00:13:33,869 I really hope you learned
485 00:13:33,880 –> 00:13:35,789 something today and that
486 00:13:35,799 –> 00:13:37,030 you can apply these
487 00:13:37,039 –> 00:13:38,390 results in other
488 00:13:38,400 –> 00:13:39,510 applications.
489 00:13:40,260 –> 00:13:42,140 If you see a monotonically
490 00:13:42,150 –> 00:13:43,479 increasing function,
491 00:13:43,489 –> 00:13:44,840 now you can
492 00:13:44,849 –> 00:13:46,289 construct the Lebesgue Stieltjes
493 00:13:46,690 –> 00:13:48,000 measure for this function.
494 00:13:48,690 –> 00:13:50,429 Well, thank you for listening
495 00:13:50,440 –> 00:13:51,750 and see you next time.
496 00:13:51,849 –> 00:13:52,590 Bye.
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Quiz Content
Q1: Which function $F: \mathbb{R} \rightarrow \mathbb{R}$ is not monotonically increasing?
A1: $F(x) = x^2$
A2: $F(x) = x$
A3: $F(x) = x^3$
A4: $F(x) = \arctan(x)$
A5: $F(x) = 0$
Q2: For a monotonically increasing function $F: \mathbb{R} \rightarrow \mathbb{R}$, we can define a measure of an interval $\mu_F( [a,b) )$. How is it defined?
A1: $$\mu_F( [a,b) ) = \lim_{\varepsilon \rightarrow 0} F(b - \varepsilon) - \lim_{\varepsilon \rightarrow 0} F(a - \varepsilon) $$
A2: $$\mu_F( [a,b) ) = \lim_{\varepsilon \rightarrow 0} F(b + \varepsilon) - \lim_{\varepsilon \rightarrow 0} F(a + \varepsilon) $$
A3: $$\mu_F( [a,b) ) = F(b) - \lim_{\varepsilon \rightarrow 0} F(a - \varepsilon) $$
A4: $$\mu_F( [a,b) ) = F(b) - F(a) $$
Q3: Consider a monotonically increasing function $F: \mathbb{R} \rightarrow \mathbb{R}$ that is also right-continuous. What is correct?
A1: $\mu_F( (0,1] ) = F(1) - F(0)$
A2: $$\mu_F( [a,b) ) = \lim_{\varepsilon \rightarrow 0} F(b + \varepsilon) - \lim_{\varepsilon \rightarrow 0} F(a + \varepsilon) $$
A3: $\mu_F( [0,1) ) = F(1) - F(0)$
A4: $\mu_F( (0,1] ) = F(1)$
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Last update: 2024-10