• Title: Jordan Chains

  • Series: Abstract Linear Algebra

  • Chapter: Some matrix decompositions

  • YouTube-Title: Abstract Linear Algebra 42 | Jordan Chains

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  • Quiz Content

    Q1: Let $A \in \mathbb{C}^{n \times n}$ be a square matrix where all eigenvalues are given by $\lambda_1, \ldots, \lambda_r$. Is $A$ similar to a block diagonal matrix?

    A1: Yes, the block sizes are exactly given by the algebraic multiplicities.

    A2: Yes, the block sizes are exactly the geometric multiplicities.

    A3: No, in general it’s not possible.

    Q2: Let $A \in \mathbb{C}^{k \times k}$ be a square matrix with only one eigenvalue $\lambda$. What is always correct?

    A1: $A$ is similar to a block diagonal matrix where the blocks are given by Jordan boxes.

    A2: $A$ is diagonalizable.

    A3: $A$ is a unitary matrix.

    A4: $A$ is has two Jordan boxes of size $\alpha(\lambda)$.

    Q3: Let $N \in \mathbb{C}^{k \times k}$ be a square matrix with only one eigenvalue $\lambda=0$. What is correct?

    A1: If $x,y \in \mathrm{Ker}(N^2)$ are linearly independent and $\mathrm{Span}(x,y) \cap \mathrm{Ker}(N) = {0 }$, then $Nx, Ny$ are also linearly independent.

    A2: If $x,y \in \mathrm{Ker}(N^2)\setminus \mathrm{Ker}(N)$ are linearly independent, then $Nx, Ny$ are also linearly independent.

    A3: If $x,y \in \mathrm{Ker}(N)$ are linearly independent, then $Nx, Ny$ are also linearly independent.

    A4: If $x,y \in \mathrm{Ker}(N^2)$ are linearly independent, then $Nx = Ny$.

  • Date of video: 2025-02-18

  • Last update: 2026-01

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